he-020

# HumanEval/20

Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.

```python
from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
```

<!-- imported from OpenAI HumanEval (HumanEval/20) -->

# Auto-generated from OpenAI HumanEval HumanEval/20. Do not edit by hand.
from solution import *  # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import find_closest_elements as candidate

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)


def test_he_020():
    check(candidate)

You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.

```python
from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
    sorted_nums = sorted(numbers)
    min_diff = float('inf')
    closest_pair = (sorted_nums[0], sorted_nums[1])
    
    for i in range(len(sorted_nums) - 1):
        diff = sorted_nums[i + 1] - sorted_nums[i]
        if diff < min_diff:
            min_diff = diff
            closest_pair = (sorted_nums[i], sorted_nums[i + 1])
    
    return closest_pair
```

The user wants me to implement a function `find_closest_elements` that takes a list of floats and returns the two closest elements as a tuple (smaller, larger).

Let me think about the approach:
1. Sort the list
2. Iterate through adjacent pairs and find the minimum difference
3. Return the pair with the minimum difference

Edge cases:
- List has at least 2 elements (guaranteed by problem statement)
- Duplicate values are allowed (as shown in the second example)
- Need to return in order (smaller, larger)

Let me implement this:

```python
from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    sorted_nums = sorted(numbers)
    min_diff = float('inf')
    closest_pair = (sorted_nums[0], sorted_nums[1])
    
    for i in range(len(sorted_nums) - 1):
        diff = sorted_nums[i + 1] - sorted_nums[i]
        if diff < min_diff:
            min_diff = diff
            closest_pair = (sorted_nums[i], sorted_nums[i + 1])
    
    return closest_pair
```

This should work correctly for all cases.