he-002

# HumanEval/2

Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.

```python


def truncate_number(number: float) -> float:
    """ Given a positive floating point number, it can be decomposed into
    and integer part (largest integer smaller than given number) and decimals
    (leftover part always smaller than 1).

    Return the decimal part of the number.
    >>> truncate_number(3.5)
    0.5
    """
```

<!-- imported from OpenAI HumanEval (HumanEval/2) -->

# Auto-generated from OpenAI HumanEval HumanEval/2. Do not edit by hand.
from solution import *  # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import truncate_number as candidate

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate(3.5) == 0.5
    assert abs(candidate(1.33) - 0.33) < 1e-6
    assert abs(candidate(123.456) - 0.456) < 1e-6


def test_he_002():
    check(candidate)

You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.

To solve this problem, we need to decompose a given positive floating point number into its integer and decimal parts. The goal is to extract and return the decimal part of the number.

### Approach
The approach to solve this problem is straightforward:
1. **Extract the Integer Part**: Convert the given floating point number to an integer using Python's built-in `int()` function. This function truncates the decimal part, effectively giving the largest integer smaller than the given number.
2. **Calculate the Decimal Part**: Subtract the integer part from the original number. This subtraction yields the decimal part of the number.

This method works efficiently because the problem guarantees that the input is a positive floating point number, so we don't need to handle negative values or non-numeric inputs.

### Solution Code
```python
def truncate_number(number: float) -> float:
    return number - int(number)
```

### Explanation
- **Extracting the Integer Part**: The `int()` function is used to convert the floating point number to its integer part. For example, `int(3.5)` results in `3`.
- **Calculating the Decimal Part**: By subtracting the integer part from the original number, we isolate the decimal part. For instance, `3.5 - 3` gives `0.5`.

This approach ensures that we correctly and efficiently extract the decimal part of any positive floating point number.

Okay, I need to solve this problem where I have to write a Python function called truncate_number. The function takes a float as input and returns the decimal part of that number. Hmm, let's think about how to do this.

So, the problem says that any positive floating point number can be split into an integer part and a decimal part. The integer part is the largest integer smaller than the given number, and the decimal part is what's left, which is always less than 1.

Wait, for example, if the input is 3.5, the output should be 0.5. That makes sense. So, how do I get the decimal part?

One approach is to subtract the integer part from the original number. But how do I get the integer part? Oh right, in Python, I can use the int() function to convert the number to an integer, which effectively truncates the decimal part. So for 3.5, int(3.5) is 3. Then subtracting that from 3.5 gives 0.5, which is the desired result.

But wait, what about negative numbers? Oh, the problem says the input is a positive floating point number, so I don't have to worry about that. So I can safely use int().

Let me test this logic with another example. Suppose the input is 4.999. The integer part is 4, so subtracting gives 0.999. That's correct.

What about a number like 5.0? The decimal part should be 0.0. Using the same method, int(5.0) is 5, subtracting gives 0.0. That's correct.

So the steps are:
1. Take the input number.
2. Convert it to an integer to get the integer part.
3. Subtract this integer part from the original number to get the decimal part.

So the function can be written as:

def truncate_number(number: float) -> float:
    return number - int(number)

Wait, but what if the number is something like 1234.5678? Let's see: int(1234.5678) is 1234, subtracting gives 0.5678, which is correct.

I think this should handle all cases as per the problem statement. So the code is straightforward.