he-019

# HumanEval/19

Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.

```python
from typing import List


def sort_numbers(numbers: str) -> str:
    """ Input is a space-delimited string of numberals from 'zero' to 'nine'.
    Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
    Return the string with numbers sorted from smallest to largest
    >>> sort_numbers('three one five')
    'one three five'
    """
```

<!-- imported from OpenAI HumanEval (HumanEval/19) -->

# Auto-generated from OpenAI HumanEval HumanEval/19. Do not edit by hand.
from solution import *  # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import sort_numbers as candidate

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate('') == ''
    assert candidate('three') == 'three'
    assert candidate('three five nine') == 'three five nine'
    assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'
    assert candidate('six five four three two one zero') == 'zero one two three four five six'


def test_he_019():
    check(candidate)

You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.

To solve this problem, we need to sort a space-delimited string of number words from 'zero' to 'nine' in ascending numerical order. The goal is to convert the words into their corresponding numerical values, sort them, and then convert them back to words in the correct order.

### Approach
1. **Mapping Words to Numbers**: Create a dictionary that maps each number word to its corresponding integer value. This allows us to easily convert each word to a number for sorting purposes.
2. **Splitting the Input String**: Convert the input string into a list of words using the `split()` method.
3. **Sorting the Words**: Use the `sorted()` function with a custom key that maps each word to its corresponding number. This ensures that the words are sorted based on their numerical values.
4. **Joining the Sorted Words**: Convert the sorted list of words back into a single string with spaces separating each word.

### Solution Code
```python
from typing import List

def sort_numbers(numbers: str) -> str:
    word_to_num = {
        'zero': 0,
        'one': 1,
        'two': 2,
        'three': 3,
        'four': 4,
        'five': 5,
        'six': 6,
        'seven': 7,
        'eight': 8,
        'nine': 9
    }
    words = numbers.split()
    sorted_words = sorted(words, key=lambda x: word_to_num[x])
    return ' '.join(sorted_words)
```

### Explanation
1. **Mapping Words to Numbers**: The dictionary `word_to_num` is used to convert each word into its corresponding integer value. This is crucial for sorting the words based on their numerical order.
2. **Splitting the Input String**: The input string is split into a list of words using `split()`, which handles the space-delimited format.
3. **Sorting the Words**: The `sorted()` function is used with a lambda function as the key to sort the words based on their numerical values. This ensures that the words are ordered from the smallest to the largest number.
4. **Joining the Sorted Words**: The sorted list of words is joined back into a single string using `' '.join()`, which ensures the words are separated by spaces in the correct order.

This approach efficiently handles the conversion, sorting, and re-conversion processes to achieve the desired result.

Okay, I need to solve this problem where I have to sort a string of number words from smallest to largest. The input is a space-delimited string of words like 'zero', 'one', up to 'nine'. The output should be the same words sorted in ascending numerical order.

First, I should think about how to approach this. So, the steps are: take the input string, split it into individual words, convert each word to its corresponding numerical value, sort those values, and then convert them back to the words in the correct order.

Wait, but how do I map each word to its numerical value? I can create a dictionary where each key is the word and the value is the integer it represents. Like, 'zero' maps to 0, 'one' to 1, and so on up to 'nine' which is 9.

So, the plan is:

1. Create a mapping from word to number.
2. Split the input string into a list of words.
3. For each word, look up its corresponding number using the dictionary.
4. Sort the list based on these numerical values.
5. Then, convert the sorted numerical values back into their word forms.
6. Join these words into a single string separated by spaces.

Let me think about the details. For example, the sample input is 'three one five'. Splitting gives ['three', 'one', 'five']. Mapping gives 3, 1, 5. Sorting these gives [1,3,5], which correspond to 'one', 'three', 'five'. So the output is 'one three five'.

So, the first thing is to build the mapping. I'll create a dictionary where each key is the word and the value is the integer. Let's list them all:

word_to_num = {
    'zero': 0,
    'one': 1,
    'two': 2,
    'three': 3,
    'four': 4,
    'five': 5,
    'six': 6,
    'seven': 7,
    'eight': 8,
    'nine': 9
}

Yes, that's correct.

Next, I'll split the input string into a list. For example, numbers.split() will give me the list of words.

Then, for each word in this list, I'll get its numerical value. So, I can create a list of tuples where each tuple is (word, number), but perhaps it's easier to just sort the list of words based on their numerical value.

Wait, in Python, the sorted function can take a key. So, I can sort the list of words using the key as the value from the dictionary.

So, the sorted list would be sorted_words = sorted(words, key=lambda x: word_to_num[x])

Yes, that makes sense.

Once I have the sorted list of words, I can join them into a string with spaces.

Putting it all together:

- Create the word_to_num dictionary.
- Split the input into words.
- Sort the words using the dictionary as the key.
- Join the sorted words into a string.

Now, let's think about edge cases. What if the input is an empty string? According to the problem statement, probably the input is always valid, but perhaps the function should handle empty strings gracefully. But the problem says the input is a space-delimited string of numberals, so maybe it's non-empty. But perhaps in the code, we should handle cases where the input is empty, but the problem's examples don't cover that.

Another case: what if the input has repeated words? Like 'two two one'. The sorted output should be 'one two two'.

So, the code should handle that correctly.

Now, let's think about the code structure.

The function is called sort_numbers and takes a string numbers as input.

Inside the function:

1. Create the word_to_num dictionary.
2. Split the input into a list of words. So, words = numbers.split()
3. Sort the words using the key from the dictionary.
4. Join the sorted words into a string with spaces.

So, the code would look like:

def sort_numbers(numbers: str) -> str:
    word_to_num = {
        'zero': 0,
        'one': 1,
        'two': 2,
        'three': 3,
        'four': 4,
        'five': 5,
        'six': 6,
        'seven': 7,
        'eight': 8,
        'nine': 9
    }
    words = numbers.split()
    sorted_words = sorted(words, key=lambda x: word_to_num[x])
    return ' '.join(sorted_words)

Wait, but what if the input is an empty string? Then, numbers.split() returns an empty list, and ' '.join would return an empty string, which is correct.

Testing the sample input: 'three one five' becomes ['three', 'one', 'five'], which when sorted gives ['one', 'three', 'five'], joined as 'one three five' which matches the sample output.

Another test case: 'zero nine eight' should become 'zero eight nine'.

Yes, that seems correct.

I think this should handle all cases correctly.