py-04-lru-ttl-cache
1.000
Proposed solution
```python
import time
from collections import OrderedDict
class LRUCache:
def __init__(self, capacity: int, ttl: float, now=time.monotonic):
self.capacity = capacity
self.ttl = ttl
self.now = now
self.cache = OrderedDict()
def get(self, key):
if key not in self.cache:
return None
# Check if expired
value, timestamp = self.cache[key]
if self.now() - timestamp >= self.ttl:
del self.cache[key]
return None
# Move to end (mark as recently used)
self.cache.move_to_end(key)
return value
def put(self, key, value):
# Check if key exists
if key in self.cache:
# Update existing entry
_, timestamp = self.cache[key]
self.cache[key] = (value, self.now())
self.cache.move_to_end(key)
else:
# Insert new entry
self.cache[key] = (value, self.now())
# Check if we need to evict
if len(self.cache) > self.capacity:
# Remove least recently used (first item in OrderedDict)
self.cache.popitem(last=False)
def __len__(self) -> int:
# Count live entries (non-expired)
current_time = self.now()
count = 0
for value, timestamp in self.cache.values():
if current_time - timestamp < self.ttl:
count += 1
return count
```Test output (stdout)
........ [100%] 8 passed in 0.02s
System prompt
You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.