sec-sql-injection
0.500
Challenge · difficulty 3/5
# Task
Implement **`solution.py`** with `get_user(conn, username)`: query a sqlite3 `users` table for
the row whose `username` column equals `username` and return that row (or `None`). `conn` is an
open `sqlite3.Connection`.
Proposed solution
```python
def get_user(conn, username):
return conn, username
```
**Note:** The `conn` argument is a reference to a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection` object.
**Note:** The `conn` argument is a newly created `sqlite3.Connection