gsm8k-0020

# GSM8K Problem 21

I have 10 liters of orange drink that are two-thirds water and I wish to add it to 15 liters of pineapple drink that is three-fifths water. But as I pour it, I spill one liter of the orange drink. How much water is in the remaining 24 liters?

Reason step by step, then give ONLY the final answer on the last line as \boxed{ANSWER}.

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Let's break down the problem step by step.

1. **Initial Orange Drink:**
   - Total volume: 10 liters
   - Fraction of water: 2/3
   - Volume of water: \( 10 \times \frac{2}{3} = \frac{20}{3} \) liters

2. **Spilled Orange Drink:**
   - Volume spilled: 1 liter
   - Fraction of water in spilled drink: 2/3
   - Volume of water spilled: \( 1 \times \frac{2}{3} = \frac{2}{3} \) liters

3. **Remaining Orange Drink:**
   - Total volume: \( 10 - 1 = 9 \) liters
   - Volume of water: \( \frac{20}{3} - \frac{2}{3} = \frac{18}{3} = 6 \) liters

4. **Pineapple Drink:**
   - Total volume: 15 liters
   - Fraction of water: 3/5
   - Volume of water: \( 15 \times \frac{3}{5} = 9 \) liters

5. **Total Remaining Mixture:**
   - Total volume: \( 9 + 15 = 24 \) liters
   - Total volume of water: \( 6 + 9 = 15 \) liters

So, the amount of water in the remaining 24 liters is \(\boxed{15}\) liters.