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he-006

1.000
1/1 tests· algorithms
Challenge · difficulty 3/5
# HumanEval/6

Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.

```python
from typing import List


def parse_nested_parens(paren_string: str) -> List[int]:
    """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
    For each of the group, output the deepest level of nesting of parentheses.
    E.g. (()()) has maximum two levels of nesting while ((())) has three.

    >>> parse_nested_parens('(()()) ((())) () ((())()())')
    [2, 3, 1, 3]
    """
```

<!-- imported from OpenAI HumanEval (HumanEval/6) -->
tests/test_he_006.py
# Auto-generated from OpenAI HumanEval HumanEval/6. Do not edit by hand.
from solution import *  # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import parse_nested_parens as candidate

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]
    assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]
    assert candidate('(()(())((())))') == [4]


def test_he_006():
    check(candidate)
System prompt
You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.
Proposed solution
```python
from typing import List

def parse_nested_parens(paren_string: str) -> List[int]:
    groups = paren_string.split()
    result = []
    for group in groups:
        max_depth = 0
        current_depth = 0
        for char in group:
            if char == '(':
                current_depth += 1
                if current_depth > max_depth:
                    max_depth = current_depth
            elif char == ')':
                current_depth -= 1
        result.append(max_depth)
    return result
```

Test output (stdout)

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1 passed in 0.01s