he-004
1.000
Challenge · difficulty 1/5
# HumanEval/4
Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.
```python
from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
>>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
1.0
"""
```
<!-- imported from OpenAI HumanEval (HumanEval/4) -->
tests/test_he_004.py
# Auto-generated from OpenAI HumanEval HumanEval/4. Do not edit by hand.
from solution import * # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import mean_absolute_deviation as candidate
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
def test_he_004():
check(candidate)
System prompt
You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.
Proposed solution
```python
from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
>>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
1.0
"""
if not numbers:
return 0.0
mean = sum(numbers) / len(numbers)
deviations = [abs(x - mean) for x in numbers]
return sum(deviations) / len(deviations)
```Test output (stdout)
. [100%] 1 passed in 0.01s