gsm8k-0020
0.000
Challenge · difficulty 2/5
# GSM8K Problem 21
I have 10 liters of orange drink that are two-thirds water and I wish to add it to 15 liters of pineapple drink that is three-fifths water. But as I pour it, I spill one liter of the orange drink. How much water is in the remaining 24 liters?
Reason step by step, then give ONLY the final answer on the last line as \boxed{ANSWER}.
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Proposed solution
Let's break down the problem step by step:
1. We start with 10 liters of orange drink that are two-thirds water. This means there are 10 * (2/3) = 6.67 liters of water in the orange drink.
2. We also have 15 liters of pineapple drink that are three-fifths water. This means there are 15 * (3/5) = 9 liters of water in the pineapple drink.
3. We pour all 10 liters of orange drink into the 15 liters of pineapple drink. Now we have a total of 10 + 15 = 25 liters of drink.
4. However, we spill 1 liter of the orange drink. So we are left with 25 - 1 = 24 liters of drink.
5. We need to find out how much water is in these 24 liters of drink.
First, let's find out how much water was in the 1 liter of orange drink that was spilled. Since the orange drink is two-thirds water, 1 liter of it would contain (2/3) * 1 = 0.67 liters of water.
Now, let's subtract this amount from the total water we had initially:
Total water = Water from orange drink + Water from pineapple drink - Water from spilled orange drink
Total water = 6.67 + 9 - 0.67
Total water = 15 - 0.67
Total water = 14.33 liters
So, the final answer is \boxed{14.33} liters of water in the remaining 24 liters of drink.