py-07-pandas-top-n
0.429
Challenge · difficulty 4/5
# Top-N rows per group (pandas)
Implement **`solution.py`** with:
```python
import pandas as pd
def top_n_per_group(df: pd.DataFrame, group_col: str, value_col: str, n: int) -> pd.DataFrame:
...
```
Given a DataFrame `df`, return a new DataFrame containing, for each group defined
by `group_col`, the **top `n` rows ranked by `value_col` in descending order**.
Requirements:
- All original columns must be preserved (do not drop, rename, or reorder columns).
- Within each group, rows are ordered by `value_col` **descending**. Groups that
have fewer than `n` rows contribute all of their rows.
- The result is ordered by group, and within each group by `value_col` descending.
Group order follows the order in which each group first appears in `df`.
- Ties in `value_col` may be broken arbitrarily, but the number of rows returned
per group must be exactly `min(n, group_size)`.
- The returned DataFrame must use a clean `RangeIndex` (`0..len-1`) — call
`reset_index(drop=True)` on the result.
- Do not mutate the input `df`.
Use pandas (e.g. `sort_values` + `groupby(...).head(n)`).
Example:
```python
df = pd.DataFrame({
"team": ["a", "a", "a", "b", "b"],
"name": ["x", "y", "z", "p", "q"],
"score": [10, 30, 20, 5, 15],
})
top_n_per_group(df, "team", "score", 2)
# team name score
# 0 a y 30
# 1 a z 20
# 2 b q 15
# 3 b p 5
```
tests/test_top_n.py
import pandas as pd
from solution import top_n_per_group
def base_df():
return pd.DataFrame({
"team": ["a", "a", "a", "b", "b"],
"name": ["x", "y", "z", "p", "q"],
"score": [10, 30, 20, 5, 15],
})
def test_basic_top2():
df = base_df()
out = top_n_per_group(df, "team", "score", 2)
assert list(out.columns) == ["team", "name", "score"]
assert len(out) == 4
a = out[out["team"] == "a"]
assert list(a["score"]) == [30, 20]
assert list(a["name"]) == ["y", "z"]
b = out[out["team"] == "b"]
assert list(b["score"]) == [15, 5]
def test_index_is_rangeindex():
df = base_df()
out = top_n_per_group(df, "team", "score", 2)
assert list(out.index) == [0, 1, 2, 3]
def test_group_smaller_than_n():
df = base_df()
out = top_n_per_group(df, "team", "score", 10)
# all rows kept (3 in a, 2 in b)
assert len(out) == 5
assert (out["team"] == "a").sum() == 3
assert (out["team"] == "b").sum() == 2
def test_n_equals_one():
df = base_df()
out = top_n_per_group(df, "team", "score", 1)
assert len(out) == 2
assert set(out["name"]) == {"y", "q"}
def test_does_not_mutate_input():
df = base_df()
snapshot = df.copy()
_ = top_n_per_group(df, "team", "score", 2)
pd.testing.assert_frame_equal(df, snapshot)
def test_group_order_follows_first_appearance():
df = pd.DataFrame({
"g": ["z", "a", "z", "a"],
"v": [1, 2, 3, 4],
})
out = top_n_per_group(df, "g", "v", 1)
# "z" appears first, so it should come first
assert list(out["g"]) == ["z", "a"]
assert list(out["v"]) == [3, 4]
def test_preserves_extra_columns():
df = pd.DataFrame({
"team": ["a", "a", "b"],
"score": [1, 2, 3],
"extra": ["p", "q", "r"],
})
out = top_n_per_group(df, "team", "score", 1)
assert list(out.columns) == ["team", "score", "extra"]
a = out[out["team"] == "a"].iloc[0]
assert a["extra"] == "q"
System prompt
You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.Proposed solution
```python
import pandas as pd
def top_n_per_group(df: pd.DataFrame, group_col: str, value_col: str, n: int) -> pd.DataFrame:
# Group by the specified column, sort within each group by the value column in descending order
# and limit the number of rows to n. Then, reset the index to get a clean RangeIndex.
result = df.groupby(group_col, group_keys=False).apply(
lambda x: x.sort_values(value_col, ascending=False).head(n)
).reset_index(drop=True)
return result
```Test output (stdout)
ibs/index.pyx:197: in pandas._libs.index.IndexEngine.get_loc
???
pandas/_libs/hashtable_class_helper.pxi:7668: in pandas._libs.hashtable.PyObjectHashTable.get_item
???
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
> ???
E KeyError: 'g'
pandas/_libs/hashtable_class_helper.pxi:7676: KeyError
The above exception was the direct cause of the following exception:
def test_group_order_follows_first_appearance():
df = pd.DataFrame({
"g": ["z", "a", "z", "a"],
"v": [1, 2, 3, 4],
})
out = top_n_per_group(df, "g", "v", 1)
# "z" appears first, so it should come first
> assert list(out["g"]) == ["z", "a"]
^^^^^^^^
test_top_n.py:61:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
/home/psc/miniconda3/lib/python3.12/site-packages/pandas/core/frame.py:4378: in __getitem__
indexer = self.columns.get_loc(key)
^^^^^^^^^^^^^^^^^^^^^^^^^
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
self = Index(['v'], dtype='str'), key = 'g'
def get_loc(self, key):
"""
Get integer location, slice or boolean mask for requested label.
Parameters
----------
key : label
The key to check its location if it is present in the index.
Returns
-------
int if unique index, slice if monotonic index, else mask
Integer location, slice or boolean mask.
See Also
--------
Index.get_slice_bound : Calculate slice bound that corresponds to
given label.
Index.get_indexer : Computes indexer and mask for new index given
the current index.
Index.get_non_unique : Returns indexer and masks for new index given
the current index.
Index.get_indexer_for : Returns an indexer even when non-unique.
Examples
--------
>>> unique_index = pd.Index(list("abc"))
>>> unique_index.get_loc("b")
1
>>> monotonic_index = pd.Index(list("abbc"))
>>> monotonic_index.get_loc("b")
slice(1, 3, None)
>>> non_monotonic_index = pd.Index(list("abcb"))
>>> non_monotonic_index.get_loc("b")
array([False, True, False, True])
"""
casted_key = self._maybe_cast_indexer(key)
try:
return self._engine.get_loc(casted_key)
except KeyError as err:
if isinstance(casted_key, slice) or (
isinstance(casted_key, abc.Iterable)
and any(isinstance(x, slice) for x in casted_key)
):
raise InvalidIndexError(key) from err
> raise KeyError(key) from err
E KeyError: 'g'
/home/psc/miniconda3/lib/python3.12/site-packages/pandas/core/indexes/base.py:3648: KeyError
_________________________ test_preserves_extra_columns _________________________
def test_preserves_extra_columns():
df = pd.DataFrame({
"team": ["a", "a", "b"],
"score": [1, 2, 3],
"extra": ["p", "q", "r"],
})
out = top_n_per_group(df, "team", "score", 1)
> assert list(out.columns) == ["team", "score", "extra"]
E AssertionError: assert ['score', 'extra'] == ['team', 'score', 'extra']
E
E At index 0 diff: 'score' != 'team'
E Right contains one more item: 'extra'
E Use -v to get more diff
test_top_n.py:72: AssertionError
=========================== short test summary info ============================
FAILED test_top_n.py::test_basic_top2 - AssertionError: assert ['name', 'scor...
FAILED test_top_n.py::test_group_smaller_than_n - KeyError: 'team'
FAILED test_top_n.py::test_group_order_follows_first_appearance - KeyError: 'g'
FAILED test_top_n.py::test_preserves_extra_columns - AssertionError: assert [...
4 failed, 3 passed in 0.28s
Self-repair attempts
[
{
"total": 7,
"answer": "```python\nimport pandas as pd\n\ndef top_n_per_group(df: pd.DataFrame, group_col: str, value_col: str, n: int) -> pd.DataFrame:\n # Group by the specified column, sort within each group by the value column in descending order\n # and limit the number of rows to n. Then, reset the index to get a clean RangeIndex.\n result = df.groupby(group_col, group_keys=False).apply(\n lambda x: x.sort_values(value_col, ascending=False).head(n)\n ).reset_index(drop=True)\n \n return result\n```",
"passed": 3,
"test_error": " Integer location, slice or boolean mask.\n \n See Also\n --------\n Index.get_slice_bound : Calculate slice bound that corresponds to\n given label.\n Index.get_indexer : Computes indexer and mask for new index given\n the current index.\n Index.get_non_unique : Returns indexer and masks for new index given\n the current index.\n Index.get_indexer_for : Returns an indexer even when non-unique.\n \n Examples\n --------\n >>> unique_index = pd.Index(list(\"abc\"))\n >>> unique_index.get_loc(\"b\")\n 1\n \n >>> monotonic_index = pd.Index(list(\"abbc\"))\n >>> monotonic_index.get_loc(\"b\")\n slice(1, 3, None)\n \n >>> non_monotonic_index = pd.Index(list(\"abcb\"))\n >>> non_monotonic_index.get_loc(\"b\")\n array([False, True, False, True])\n \"\"\"\n casted_key = self._maybe_cast_indexer(key)\n try:\n return self._engine.get_loc(casted_key)\n except KeyError as err:\n if isinstance(casted_key, slice) or (\n isinstance(casted_key, abc.Iterable)\n and any(isinstance(x, slice) for x in casted_key)\n ):\n raise InvalidIndexError(key) from err\n> raise KeyError(key) from err\nE KeyError: 'g'\n\n/home/psc/miniconda3/lib/python3.12/site-packages/pandas/core/indexes/base.py:3648: KeyError\n_________________________ test_preserves_extra_columns _________________________\n\n def test_preserves_extra_columns():\n df = pd.DataFrame({\n \"team\": [\"a\", \"a\", \"b\"],\n \"score\": [1, 2, 3],\n \"extra\": [\"p\", \"q\", \"r\"],\n })\n out = top_n_per_group(df, \"team\", \"score\", 1)\n> assert list(out.columns) == [\"team\", \"score\", \"extra\"]\nE AssertionError: assert ['score', 'extra'] == ['team', 'score', 'extra']\nE \nE At index 0 diff: 'score' != 'team'\nE Right contains one more item: 'extra'\nE Use -v to get more diff\n\ntest_top_n.py:72: AssertionError\n=========================== short test summary info ============================\nFAILED test_top_n.py::test_basic_top2 - AssertionError: assert ['name', 'scor...\nFAILED test_top_n.py::test_group_smaller_than_n - KeyError: 'team'\nFAILED test_top_n.py::test_group_order_follows_first_appearance - KeyError: 'g'\nFAILED test_top_n.py::test_preserves_extra_columns - AssertionError: assert [...\n4 failed, 3 passed in 0.28s"
},
{
"total": 7,
"answer": "```python\nimport pandas as pd\n\ndef top_n_per_group(df: pd.DataFrame, group_col: str, value_col: str, n: int) -> pd.DataFrame:\n # Group by the specified column, sort within each group by the value column in descending order\n # and limit the number of rows to n. Then, reset the index to get a clean RangeIndex.\n # Ensure that the result preserves all original columns.\n result = df.groupby(group_col, as_index=False)[[group_col, value_col]].apply(\n lambda x: x.sort_values(value_col, ascending=False).head(n)\n ).reset_index(drop=True)\n \n # Add back any extra columns that were not in the groupby columns\n extra_cols = df.columns.difference([group_col, value_col])\n result = pd.merge(result, df.loc[:, extra_cols], on=group_col, how='left')\n \n return result\n```",
"passed": 0,
"test_error": "^^^^^^^^^^^^\n_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ \n\nself = extra\n0 p\n1 q\n2 r, key = 'team', axis = 0\n\n @final\n def _get_label_or_level_values(self, key: Level, axis: AxisInt = 0) -> ArrayLike:\n \"\"\"\n Return a 1-D array of values associated with `key`, a label or level\n from the given `axis`.\n \n Retrieval logic:\n - (axis=0): Return column values if `key` matches a column label.\n Otherwise return index level values if `key` matches an index\n level.\n - (axis=1): Return row values if `key` matches an index label.\n Otherwise return column level values if 'key' matches a column\n level\n \n Parameters\n ----------\n key : Hashable\n Label or level name.\n axis : int, default 0\n Axis that levels are associated with (0 for index, 1 for columns)\n \n Returns\n -------\n np.ndarray or ExtensionArray\n \n Raises\n ------\n KeyError\n if `key` matches neither a label nor a level\n ValueError\n if `key` matches multiple labels\n \"\"\"\n axis = self._get_axis_number(axis)\n first_other_axes = next(\n (ax for ax in range(self._AXIS_LEN) if ax != axis), None\n )\n \n if self._is_label_reference(key, axis=axis):\n self._check_label_or_level_ambiguity(key, axis=axis)\n if first_other_axes is None:\n raise ValueError(\"axis matched all axes\")\n values = self.xs(key, axis=first_other_axes)._values\n elif self._is_level_reference(key, axis=axis):\n values = self.axes[axis].get_level_values(key)._values\n else:\n> raise KeyError(key)\nE KeyError: 'team'\n\n/home/psc/miniconda3/lib/python3.12/site-packages/pandas/core/generic.py:1776: KeyError\n=========================== short test summary info ============================\nFAILED test_top_n.py::test_basic_top2 - KeyError: 'team'\nFAILED test_top_n.py::test_index_is_rangeindex - KeyError: 'team'\nFAILED test_top_n.py::test_group_smaller_than_n - KeyError: 'team'\nFAILED test_top_n.py::test_n_equals_one - KeyError: 'team'\nFAILED test_top_n.py::test_does_not_mutate_input - KeyError: 'team'\nFAILED test_top_n.py::test_group_order_follows_first_appearance - KeyError: 'g'\nFAILED test_top_n.py::test_preserves_extra_columns - KeyError: 'team'\n7 failed in 0.46s"
},
{
"total": 7,
"answer": "```python\nimport pandas as pd\n\ndef top_n_per_group(df: pd.DataFrame, group_col: str, value_col: str, n: int) -> pd.DataFrame:\n # Group by the specified column, sort within each group by the value column in descending order\n # and limit the number of rows to n. Then, reset the index to get a clean RangeIndex.\n # Ensure that the result preserves all original columns.\n result = df.groupby(group_col, as_index=False)[[group_col, value_col]].apply(\n lambda x: x.sort_values(value_col, ascending=False).head(n)\n ).reset_index(drop=True)\n \n # Add back any extra columns that were not in the groupby columns\n extra_cols = df.columns.difference([group_col, value_col])\n result = pd.merge(result, df.loc[:, extra_cols], on=group_col, how='left')\n \n return result\n```",
"passed": 0,
"test_error": ""
}
]