he-020

# HumanEval/20

Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.

```python
from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
```

<!-- imported from OpenAI HumanEval (HumanEval/20) -->

# Auto-generated from OpenAI HumanEval HumanEval/20. Do not edit by hand.
from solution import *  # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import find_closest_elements as candidate

METADATA = {
    'author': 'jt',
    'dataset': 'test'
}


def check(candidate):
    assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
    assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
    assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
    assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)


def test_he_020():
    check(candidate)

You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.

```python
from typing import List, Tuple


def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
    """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each
    other and return them in order (smaller number, larger number).
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
    (2.0, 2.2)
    >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
    (2.0, 2.0)
    """
    min_diff = float('inf')
    result = (numbers[0], numbers[1])
    
    for i in range(len(numbers)):
        for j in range(i + 1, len(numbers)):
            diff = abs(numbers[i] - numbers[j])
            if diff < min_diff:
                min_diff = diff
                if numbers[i] <= numbers[j]:
                    result = (numbers[i], numbers[j])
                else:
                    result = (numbers[j], numbers[i])
                    
    return result
```