he-018
1.000
Challenge · difficulty 2/5
# HumanEval/18
Implement a file **`solution.py`** that completes the function below. Keep the given name and signature; your file must define it at module level.
```python
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
```
<!-- imported from OpenAI HumanEval (HumanEval/18) -->
tests/test_he_018.py
# Auto-generated from OpenAI HumanEval HumanEval/18. Do not edit by hand.
from solution import * # noqa: F401,F403 (prompt helpers may be referenced by tests)
from solution import how_many_times as candidate
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('', 'x') == 0
assert candidate('xyxyxyx', 'x') == 4
assert candidate('cacacacac', 'cac') == 4
assert candidate('john doe', 'john') == 1
def test_he_018():
check(candidate)
System prompt
You are an expert programmer. Solve the task exactly as specified. Output your solution as fenced code blocks using the required file name(s) and the exact function/type signatures requested. Prefer correctness; do not include prose outside code unless asked.
Proposed solution
```python
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
if not substring:
return 0
count = 0
start = 0
while True:
pos = string.find(substring, start)
if pos == -1:
break
count += 1
start = pos + 1
return count
```Test output (stdout)
. [100%] 1 passed in 0.01s