gsm8k-0007

# GSM8K Problem 8

Carla is downloading a 200 GB file. Normally she can download 2 GB/minute, but 40% of the way through the download, Windows forces a restart to install updates, which takes 20 minutes. Then Carla has to restart the download from the beginning. How load does it take to download the file?

Reason step by step, then give ONLY the final answer on the last line as \boxed{ANSWER}.

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To find the total time it takes to download the file, we need to break down the process into distinct phases: the initial download before the interruption, the interruption itself, and the full download after the restart.

1.  **Calculate the time for the initial download phase:**
    *   The total file size is 200 GB.
    *   Carla downloads 40% of the file before the interruption.
    *   Size downloaded = $200 \text{ GB} \times 0.40 = 80 \text{ GB}$.
    *   The download speed is 2 GB/minute.
    *   Time taken for this phase = $\frac{80 \text{ GB}}{2 \text{ GB/minute}} = 40 \text{ minutes}$.

2.  **Calculate the time for the interruption:**
    *   Windows forces a restart which takes 20 minutes.
    *   Time taken for this phase = 20 minutes.

3.  **Calculate the time for the full download phase:**
    *   After the restart, Carla has to restart the download from the beginning. This means she must download the entire 200 GB file again.
    *   Total file size = 200 GB.
    *   Download speed = 2 GB/minute.
    *   Time taken for this phase = $\frac{200 \text{ GB}}{2 \text{ GB/minute}} = 100 \text{ minutes}$.

4.  **Calculate the total time:**
    *   Total Time = (Time for initial phase) + (Time for interruption) + (Time for full download)
    *   Total Time = $40 \text{ minutes} + 20 \text{ minutes} + 100 \text{ minutes}$
    *   Total Time = 160 minutes.

\boxed{160 \text{ minutes}}